A curved road is banked. There is a car on the curve. The acceleration of gravit
ID: 2025464 • Letter: A
Question
A curved road is banked. There is a car on the curve. The acceleration of gravity is 9.8 m/s^2
What is the component of its weight parallel to the incline?
bank is 24 degrees and the mass of the car is 2Mg (not kg)
The next curve that car approaches has a radius of curvature of 88.9m. It is banked at an angle of 30 degrees. The ideal speed for this curve is Vc (banked so that the car experiences no friction force). The speed of the car is Vs as it rounds the curve is Vs = 1.34 Vc.
The frictional force keeps the car from
1. the frictional force is zero.
2. moving in a circular path.
3. sliding towards the center of curvature.
4. sliding away from the center of curvature.
Explanation / Answer
The answer is 4.sliding away from the center of curvature. If Vc is multiplied by a number less than 1 then it would have been sliding away towards the center of curvature.
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