Three 4.00 ohms resistors are connected in series to a 12.0 V Battery. A) What i

Question

Three 4.00 ohms resistors are connected in series to a 12.0 V Battery.
A) What is the equivalent resistance of the circuit?
B) What is the current through each resistor

Next question

What resistance should be connected in parallel with a 75.0 ohm resistor and 220 V battery so that the total current in the circuit is 5.00 A?

Last Questions

A circuit with a 6.00 V battery has a 2.50 ohm resistor and a 10.0 ohm resistor connected in parallel.

A) what is the potential difference across each resistor

B) what is the current through each resistor?

C) What is the power dissipated by each resistor?

Explanation / Answer

Three 4.00 ohms resistors are connected in series to a 12.0 V Battery.
A) What is the equivalent resistance of the circuit?
B) What is the current through each resistor

R1=R2=R3=4 Ohm
V=12 V
These resistors are connected in series
A) So Req=R1+R2+R3=4+4+4=12 Ohm
B) In series connection current in the circuit is constant
I=V/R=12/12= 1 A

What resistance should be connected in parallel with a 75.0 ohm resistor and 220 V battery so that the total current in the circuit is 5.00 A?

V=220 v
R1=75 Ohm
I=5 A
So Req=V/I=220/5=44 Ohm

So R1!!R2=44
1/R1+1/R2=1/44
1/75+1/R2=1/44
1/R2=1/44-1/75
1/R2=9.39*10^-3
R2=106.45 ohm

A circuit with a 6.00 V battery has a 2.50 ohm resistor and a 10.0 ohm resistor connected in parallel.

A) what is the potential difference across each resistor

B) what is the current through each resistor?

C) What is the power dissipated by each resistor?

V=6.00V
R1=2.5 Ohm, R2=10 ohm connected in parallel
A) in parallel circuit potential difference remains constant so it is 6 for each resistors
B)
I1=V/R1=6/2.5=2.4 A
I2=V/R2=6/10=0.6 A

C)
P1= V*I1=6*2.4=14.4 W
P2=V*I2=6*0.6=3.6 W

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