Chapter 26, Problem 017 GO Light in a vacuum is incident on a transparent glass

Question

Chapter 26, Problem 017 GO Light in a vacuum is incident on a transparent glass slab. The angle of incidence is 32.7. The slab is then immersed in a pool of liquid. When the angle of incidence for the light striking the slab is 22.9°, the angle of refraction for the light entering the slab is the same as when the slab was in a vacuum. What is the index of refraction of the liquid? Number Units No units the tolerance is +/-6% sHoW HT HINT TEXT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Question Attempts: Unlmited SAVE FOR LATER SUBHIT ANSWER Earn Maximum Points available only if you answer this question correctly in four attempts or less.

Explanation / Answer

ng = index of refraction of glass

na = index of refraction of air = 1

ia = incident angle in air = 32.7 deg

rg = angle of refraction angle in glass

Using the snell's law

na Sinia = ng Sinrg

1 Sin32.7 = ng Sinrg

ng Sinrg = 0.54 eq-1

inside the liquid

nl = index of refraction of the liquid = ?

il = angle of incidence in liquid = 22.9 deg

Using snell's law

nl Sinil = ng Sinrg

nl Sin22.9 = 0.54 using eq-1

nl = 1.4

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