A long straight wire suspended in the air carries a conventional current of 6.6

Question

A long straight wire suspended in the air carries a conventional current of 6.6 amperes in the-x direction as shown (the wire runs along the x-axis). At a particular instant an electron at location 0,-0.003, o m has velocity-2.5 x 105,-3 x 105, o > m/s. z out (a) What is the magnetic field due to the wire at the location of the electron? tesla (b) What is the magnetic force on the electron due to the current in the wire? (c) If the moving particle were a proton instead of an electron, what would the magnetic force on the proton be?

Explanation / Answer

a)

The mangetic field

B =uoI/ [ 2 ? r ]

B = ( 4pi*10-7 ) ( 6.6 ) / [ 2pi * 0.003 ]=4.4*10-4 T

B=<0 , 0 ,4.4*10-4 > T

b)

Magnetic force is given by

F=q(v x B),

F =(-1.6*10-19) [< -2.5*105 , -3*105 , 0 > x <   0 , 0 , 4.4*10-4 >]

F =< 2.112*10-17 , -1.76*10-17 , 0 > N

c )

F=q(v x B),

F =(1.6*10-19) [< -2.5*105 , -3*105 , 0 > x <   0 , 0 , 4.4*10-4 >]

F =< -2.112*10-17 ,+1.76*10-17 , 0 > N

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