GENERAL PHYSICS PHY204 9 9.12kV D) 4.26 kV E) None of these LORIDA AT WL.CA 6. A
ID: 2036338 • Letter: G
Question
GENERAL PHYSICS PHY204 9 9.12kV D) 4.26 kV E) None of these LORIDA AT WL.CA 6. A uniform magnetio field of magnitude 0.N0 T in the egative s-direction is present in a region of space, as shown in the Rigure below. A un orm electric feld is ales proton that is projected with an inisial veloeity e4.510 /s in the postive s direction passes through the region without deflection. What is thhe electrie field vecte the region? 0.80T A) -36 kV/m B) +36 kV/m f C) +73 kV/mf D) -73 kV/mj a) None of these 7. A positively charged particle is moving to the right, directly above a wire having ae current hlowing to the right, as shown in the figure. In which direction is the magnetic force exerted on the particle? +Q A) into the page B) out of the page C) downward D) upward E) The magnetic force is zero since the velocity is parallel to the current. currents in same directions. From your point of view, the magnetic field at the point exactly midway between the two wires A) points upward. B) points downward. C) points toward you D) points away from you E) is zero. 8. Two long parallel wires placed side-by-side on a horizontal table carry identical size Pa A B C 0 A BExplanation / Answer
6.
B = magnetic field = - 0.80 k
vo = initial velocity = 4.5 x 104 i
for the proton to pass undeflected
vo x B = E
( 4.5 x 104 i ) x (- 0.80 k) = E
E = 3.6 x 104 j
E = 36 k V/m j
7.
at the location of particle , the magnetic field due to the current carrying wire comes out to be in outward direction.
Using right hand rule , the direction of magnetic force on the charged particle comes out to be in down direction towards the wire
so choice C
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