2. /2.5 points My Notes Ask Your Teacher P9A A 25.0 gram bullet traveling at 250

Question

2. /2.5 points My Notes Ask Your Teacher P9A A 25.0 gram bullet traveling at 250 m/s parallel to the (Theta 30.00) incline impacts, and imbeds itself in a block of wood (m 1.40 kg) initially at rest. If there is no friction acting between the block and the incline, determine the maximum distance d the block moves up the incline. 3. /2.5 points My Notes Ask Your Teacher P9B A 0.650 kg wad of clay is traveling horizontally when it impacts and sticks to a stationary block of wood (mw1.15 kg). The combined masses slide across a horizontal, frictionless surface and impact an initially relaxed spring (k = 150 N/m). If the maximum compression of the spring is 0.220 m, determine the initial speed of the clay. ci 0 Initial speed:

Explanation / Answer

1) Using conservation of momentum,

mv = (m+M)vf where m - mass of bullet, M is mass of block

0.025*250 = (0.025 + 1.40)vf

vf = 4.3859 m/s

suppose, before the bullet strikes the block,,the block was at height h = 0, so vf found above becomes v initial and as the block and bullet stops, vf = 0

0 + 1/2mTv2 = mgh + 1/2mvf2

0.5* 1.425*4.38592 = 1.425*9.81*h

h = 13.7057 / 13.9793

h = 0.98043 m

so, distance travelled d = h / sin (theta)

d = 0.98043 / sin 30

d = 1.96086 m

2) In this question, just equate the kinetic energy and elastic potential energy

K.E = E.P.E

1/2(M+m)V2 = 1/2kx2

(1.15 + 0.650)V2 = 150*0.222

1.8*V2 = 7.26

V = 2.0083 m/s

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