A gas expands from I to F in the figure below. The energy added to the gas by he

Question

A gas expands from I to F in the figure below. The energy added to the gas by heat is 222 3 when the gas goes from I to F along the diagonal path. P (am) 4V(liters) (a) What is the change in internal energy of the gas? Use the relations between various features of the graph and the work done on the gas to find the energy added by work and then use your result to find the change in internal energy of the gas. (b) How much energy must be added to the gas by heat for the indirect path IAF to give the same change in internal energy? Calculate the work done on the gas from the appropriate area on the graph and apply the first law of thermodynamics with the known change in internal energy and the energy transferred by heat. ?

Explanation / Answer

work done=area under the P-V diagram

=0.5*(4+1)*(4-2) atm.ltr

=506.62 J

change in internal energy=heat added - work done

=222-506.62

=-284.62 J

part b:

work done in the path IAF=4 atm*(4-2) ltr

=810.6 J

using first law of thermodynamics:

heat added=work done +change in internal energy

==>heat added=810.6-284.62

=525.98 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.