Two particles #1 and #2 with same mass but different charge are released from re

Question

Two particles #1 and #2 with same mass but different charge are released from rest at z= 1.0 mm distance above a charged thin disk (z=0) with a diameter of 0.6 m. Let us call the charge of particle #1 q1 and that of particle #2 q2. What is the ratio q1/q2, if particle #1 crosses a plane located at z= 5.0 mm distance from the disk with a speed 6 times greater than that of particle #2?

Please show all work and then match with appropriate answer below.
(brief explanations will earn automatic "lifesaver")

A. 3 B. 6 C. 12 D. 24 E. 36

Explanation / Answer

answer is E. 36

let the charge of disc be Q

then we have
Decrease in potential energy = Increase in kinetic energy
==> (q1Q)/(q2Q) = (m36v2)/(mv2)

Cancelling Q, m, and v2... we have

q1/q2= 36 ...................ans

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