In Procedure 1: a wire of length L = 9.18 cm sits on an electronic scale. There

Question

In Procedure 1: a wire of lengthL=9.18cm sits on an electronic scale. There is also a uniform mangetic field perpendicular to the wire, and along its entire length. When there is no current in the wire, the scale reads863g. When a currentI=37.6mA goes through the wire, and the scale reads848g.
NOTE: Beware of units!
NOTE: These numbers arenotlike the numbers you will actually get when you do the expermiment!

a) FindF, the magnitude of the force on the wire created by the interaction of the current and the magnetic field.
N

b) FindB, the magnitude of the magnetic field around the wire.
T

c) Suppose the direction of the magnetic field is reversed. What would the scale read now?
g

d) Suppose the system could take large currents. To what would you have to raise the current (before you reversed the direction ofB) so the force on the wire entirely supported the weight of the wire (and the scale reads zero)?
A

Explanation / Answer

a) the force is given by F = 863-848 = 15*9.81/1000 = 0.14715 N b) the magnetic field is given by B = 0.14715*1000*100/(9.18*37.6) = 42.63 T c) the reading of the scale would then be = 863-30 = 833 g. d) the value of the current is given by I = 848*9.81*100/(1000*9.18*42.63) = 2.1256 A

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