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The tension in a string from which a 7.3 kg object is suspended in an elevator i

ID: 2078065 • Letter: T

Question

The tension in a string from which a 7.3 kg object is suspended in an elevator is equal to 76 N. What is magnitude of the acceleration a of the elevator? The acceleration of gravity is 9.8 m/s^2. Answer in units of m/s^2. What is its direction? 1. not moving 2. upward 3. Downward A dragster and driver together have mass 915.6 kg. The dragster, starting from rest, attains a speed of 26.7 m/s in 0.54 s. Find the average acceleration of the dragster during this time interval. Answer in units of m/s^2. What is the size of the average force on the dragster during this time interval? Answer in units of N. Assume the driver has a mass of 72 kg. What horizontal force does the seat exert on the driver?

Explanation / Answer

46) since T> mg

the lift is moving upwards

T = mg + ma

a = (T - mg) / m

= (76 - 7.3*9.8 ) / 7.3

= 0.61 m/s2 ( moving upwards)

48 ) average acceleration = velocity / time = 26.7 / 0.54 = 49.44 m/s2

49) average force = ma = 915.6 * 49.44 = 45271.33 N

50 ) force exertes by seat = 72*0.61 = 43.92 N

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