The figure shows a model of a crane that may bemounted on a truck.A rigid unifor

Question

The figure shows a model of a crane that may bemounted on a truck.A rigid uniform horizontal bar of mass = 90.00 and length = 5.700 is supported by two verticalmassless strings.String A is attached at a distance = 1.900 from the left end of the barand is connected to the top plate. String B is attached to the leftend of the bar and is connected to the floor. An object of mass = 3500 is supported by the crane ata distance = 5.500 from the left end of the bar.Throughout this problem, positive torque is counterclockwise. Use9.81 for the magnitude of the accelerationdue to gravity. image: http://session.masteringphysics.com/problemAsset/1011194/14/MFS_nr_4.jpg Part A Find , the tension in string A. Part B Find , the magnitude of the tension instring B.

Explanation / Answer

As bar is in rotational equilibrium,taking torque at left end

Torque due to T(B) =0

Torque due to T(A) =T(A)*1.9 counterclockwise

Torque due to weight of bar = 90*9.81*5.7/2=2516.265 N clockwise

Torque due to weight of object =3500*9.81*5.5=188842.5 N clockwise

counterclockwise torque =clockwise torque

T(A)*1.9 =2516.265+188842.5=191358.765

T(A) =100715.1395 N

T(B) + m1g +m2g =T(A)

T(B)=100715.1395 -3590*9.81

T(B) =65497.24 N

(1) T(A) the tension in string A.is 100715.1395 N

(2) T(B) the magnitude of the tension in string B is 65497.24 N

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