It is determined by immersing a crown in water that its volume is 26 in 3 = 0.01

Question

It is determined by immersing a crown in water that its volume is 26 in3 = 0.015 ft3. (a) What would its weight be if it were made of pure gold? Take the density of gold to be 1,200 lb/ft3.
W =  lb

(b) What would its weight be if half of its volume were gold and half lead? Take the density of lead to be 708 lb/ft3.
W =  lb It is determined by immersing a crown in water that its volume is 26 in3 = 0.015 ft3. (a) What would its weight be if it were made of pure gold? Take the density of gold to be 1,200 lb/ft3.
W =  lb

(b) What would its weight be if half of its volume were gold and half lead? Take the density of lead to be 708 lb/ft3.
W =  lb (a) What would its weight be if it were made of pure gold? Take the density of gold to be 1,200 lb/ft3.
W =  lb

(b) What would its weight be if half of its volume were gold and half lead? Take the density of lead to be 708 lb/ft3.
W =  lb

Explanation / Answer

p_Pb = 708 lb/ft3

p_Au = 1200 lb/ft3

p_average = 0.5 * p_Pb + 0.5 * p_Au

= 0.5 * 708 + 0.5 * 1200

= 954 lb/ft3

----------------------------

m = p V

= 954 * 0.015

= 14.31 lb.

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