The following questions are from a simulation using this link: http://phet.color

Question

The following questions are from a simulation using this link: http://phet.colorado.edu/en/simulation/fluid-pressure-and-flow

1.Does the speed of the flow of the water (out of the tank) depend upon the height of the tank?  

2.Why do you suppose this is?  

3.Does the speed of the flow depend upon the fluid density?

4.What does flow speed depend upon?  

5.Explain this relationship (in your own words).  

6.What happens to the stream of fluid after it leaves the tank?  

7.Describe the path of the fluid steam.  

8.Does it remind you of anything you have seen before (in physics, not in the bathroom)?

9.What does it remind you of?  

10.How far (horizontally) will a steam of water travel if it exists the water tower at 14 m/s 10m above the ground?  

11.How far do you suppose a baseball will travel if thrown horizontally 14 m/s from the top of a 10m-high ladder?

12.Turn on the hose and leave it aimed directly upward. Adjust the other pieces of the simulation. What do you notice about the height of the little fountain created?

13.When you have your blood pressure monitored, the nurse places the cuff on your arm, just below the shoulder. Why do you suppose this is?  

14.What organ is s/he really measuring?  

The height difference between the top of the tower and the leaking hole is 10 m. Using the Bernoulli%u2019s big ol%u2019 continuity formula, to what depth would the tower need to be filled to produce a stream leaving the hole at 8.0 m/s?

15.As the stream falls it gains speed. Why is this?  

Explanation / Answer

1) yes. v = sqrt(2*g*h)

h---->tank height

2)

as the tank height increases the pressure at the bottom
increases. thats why when fluid comes out its speed increases.

3)No.

4)just height of the water colum.

5)
as the tank height increases the pressure at the bottom
increases. thats why when fluid comes out its speed increases.

6)it accelerate downward

7)


10) v = 14 m/s

h = 10 m

time taken to reach ground.
in y-direction
h = 0.5*a*t^2

t = sqrt(2*h/g) = 1.43 s

horezontal distance, R = v*t = 14*1.43 = 20 m

11)
same 20 m

12) h = v^/2*g = 10 m

14)

v = sqrt(2*g*h)

h = v^2/2*g = 8^2/(2*9.8) = 3.27 s


15) due to gravitational pull

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.