An electric field is E = 400 N/C i for x > 0 and E = -400 N/C i for x < 0. A cyl

Question

An electric field is E = 400 N/C i for x > 0 and E = -400 N/C i for x < 0. A cylinder of length 20 cm and radius 5 cm has its center at the origin and its axis along the x axis such that one end is at x = +10 cm and the other is at x = -10 cm.

(a) What is the outward flux through each end?

(b) What is the outward flux through the curved surface of the cylinder? N m2/C

(c) What is the net outward flux through the entire cylindrical surface? N m2/C

(d) What is the net charge inside the cylinder? C

Explanation / Answer

a)at +10 cm

flux=400*(3.14*25*10^-4)= 3.14 N-m^2/c

at -10 cm

flux=-400*(-3.14*25*10^-4)= 3.14 N-m^2/c

b)flux_curved=0

c)total flux=6.28 M-m^2/c

d)q=flux*e0=6.28*8.85*10^-12= 55.578 *10^-12 C

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