A ball is thrown directly upward with an initial velocity of 7.17m/s, what is th

Question

A ball is thrown directly upward with an initial velocity of 7.17m/s, what is the maximum height that the ball can reach.

This was a part of an exam question, I realize now that I should have used a one dimensional kinematics equation, however at the time of the test I was blanking on this part and instead decided to use a two dimensional kinematic equation. I used the two dimensional equation y=yo+Voyt-1/2gt^2

With yo=0  Voy=7.17m/s  and since Vo=0 at the highest point(the peak of the parabola) I figured Voy=gt therefore t=Voy/g

I then swapped in Voy/g for all t in the quation and solved for y.

g=-9.81m/s^2

Can this work?

Explanation / Answer

max height when vy = 0

so vy^2 = v0y^2 + 2 a y

0 = 7.17^2 - 2*9.81*y

y=2.62 m

your method can work

t = 7.17/9.81=0.73

so y = 7.17*0.73-0.5*9.81*0.73^2=2.62 m

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