Calculate the speed of the proton after 19 ns. Answer in units of m/s A charged

Question

Calculate the speed of the proton after 19 ns. Answer in units of m/s A charged mass on the end of a light string is attached to a point on a uniformly charged vertical sheet (with areal charge density sigma = 0.24 mu C/m2) of infinite extent. Find the angle theta the thread makes with the vertically charged sheet. The acceleration due to gravity is 9.8 m/s2 and the permittivity of free space is 8.854 x 10-12 C2/N . m2. Answer in units of degree Find sigma for an angle of 75degree. Answer in units of mu C/m2

Explanation / Answer

22)electric field due to a sheet of charge= sigma/2eo

so,

balancing the forces, perpendicular to the string,

tan theta=q(sigma/2e)/(mg)

=(0.24*10^-6*0.11*10^-6)/(2*8.85*10^-12*10^-3*9.8)

=0.1522

so theta=8.65 degrees

23)tan75=x*0.11*10^-6/(2*8.85*10^-12*10^-3*9.8)

or 3.73=x*0.11*10^-6/(2*8.85*10^-12*10^-3*9.8)

or x=5.88*10^-6 C/m^2

=5.88 uC/m^2

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