The genotype of both F1 individuals in a tetrahybrid cross is AaBbCcDd. Assume t

Question

The genotype of both F1 individuals in a tetrahybrid cross is AaBbCcDd. Assume that the parents were AABBCCDD and aabbccdd and that crossing over does not occur in the crosses producing both the F1 and the F2. Also assume that the first and third genes are linked but that the second and fourth genes show independent assortment from them and each other. What is the probability that F2 offspring will have the (a) AaBbCCDd or (b) AaBBCcDd genotype?

Can someone please explain in detail how to do B, please?

Answers:

a- cant happen

b- 1/16

Explanation / Answer

Ans.- Since AC and Ac are linked lets just write AC together as A, then we can simplify the question the F1 is then AaBbCc the question then is what is the probability of the AaBBCcDd genotype, this can be rewritten as AaBBDd. The chances that this will come are for Aa is ½ , for BB is ¼ and for Dd is ½= ½ .1/4.1/2 = 1/16.

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