The genotype of individual #1 is EeFfGgHh, while the genotype of individual #2 i

ID: 53144 • Letter: T

Question

The genotype of individual #1 is EeFfGgHh, while the genotype of individual #2 is EeFfggHH. A cross is performed between individual #1 and #2. What is the probability of producing the following genotype among their F1 offspring (show ALL your work for full credit)?

a) Heterozygous for all 4 genes

b) Homozygous recessive for all 4 genes

c) Homozygous dominant or homozygous recessive in any combination for all 4 genes

Explanation / Answer

For the above genotypes, there are 36 different genotypes possible in the F1 offspring:

EEFFGgHH: 1.6 %

eEFFGgHH: 3.1 %

EEffGgHH: 1.6 %

eeFFGgHH: 1.6%

eeffGgHH: 1.6 %

EEFFGghH: 1.6 %

eEFFGghH: 3.1 %

EEffggHH: 1.6 %

eeFFGghH: 1.6 %

eeffggHH: 1.6 %

EEFFggHH: 1.6 %

eEFFggHH: 3.1 %

EEffGghH: 1.6 %

eeFFggHH: 1.6 %

eeffGghH: 1.6 %

EEfFGgHH: 3.1 %

eEfFGgHH: 6.3 %

EEffgghH: 1.6 %

eefFGgHH: 3.1 %

eeffgghH: 1.6 %

EEFFgghH: 1.6 %

eEFFgghH: 3.1 %

eEffGgHH: 3.1 %

eeFFgghH: 1.6 %

EEfFggHH: 3.1 %

eEfFggHH: 6.3 %

eEffggHH: 3.1 %

eefFggHH: 3.1 %

EEfFGghH: 3.1 %

eEfFGghH: 6.3 %

eEffGghH: 3.1%

eefFGghH: 3.1

EEfFgghH: 3.1 %

eEfFgghH: 6.3 %

eEffgghH: 3.1%

eefFgghH: 3.1 %

a) The probability of Heterozygous for all four genes 0.063 (There is only one genotype heterozygous for all genes, and the probability is 6.3% or 0.063)

b) HOmozygous recessive for all genes: 0

c) Homozygous dominant EE - 0.0252, homozygous recessive ee - 0.02

Homozygous dominant FF - 0.0205, homozygous recessive ff - 0.0252