A 25 mm diameter rod is loaded axially in tension as shown. this material has a
ID: 2137888 • Letter: A
Question
A 25 mm diameter rod is loaded axially in tension as shown. this material has a poisson's ratio of 0.35. if the rod decreases in diameter by 0.0001mm while the length increases, determine.
(a) the change in length (longitudinal) due to the applied load? sigma(long)=_________________
(b) The Elastic modulus of this material? E=________________________
(c) The Shear modulus of this material? G=__________________________
(d) The change in volume of the rod? (triangle) V__________________
as shown. This material has a Poisson's ratio while the length increases, determine loadExplanation / Answer
poission's ratio n=-e_trans/e_longitudinal....
e_ trans=change in diameter/original diameter
=1*10^-4/25
=4*10^-6...
e_longitudinal =delat L/L...
change in length delta L=4*10^-6/0.35=11.43 *10^-6 m....
B)E=stree/strain=1.78*10^11 N/m^2..
C) G=E/2(1+n)=6.59*10^10 N/m^2...
D)chnge in volume=change in length*pi*(change in diameter/2)^2..
delta V=11.43 *10^-6*3.142*(0.5*10^-7)^2
delta V=8.97*10^-20 m^3.....
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