A 25 mL sample containing Cu 2+ gave an instrumentsignal of 23.6 units (correcte

Question

A 25 mL sample containing Cu2+ gave an instrumentsignal of 23.6 units (corrected for a blank). When exactly 0.5 mLof 0.0287 M Cu(NO3)2 was added to thesolution, the signal increased to 37.9 units. Calculate the molarconcentration of Cu2+ assuming that the signal wasdirectly proportional to the analyte concentration. Thanks:) A 25 mL sample containing Cu2+ gave an instrumentsignal of 23.6 units (corrected for a blank). When exactly 0.5 mLof 0.0287 M Cu(NO3)2 was added to thesolution, the signal increased to 37.9 units. Calculate the molarconcentration of Cu2+ assuming that the signal wasdirectly proportional to the analyte concentration. Thanks:)

Explanation / Answer

initial moles of Cu2+ = n mol C =concentration 23.6/37.9 = initial C of Cu2+ / final C of Cu2+ = (n x 1000/25) / [(n + 0.0287 x 0.5/ 1000) x 1000 /(25+ 0.5)]
n= 2.24 E -5
Cof Cu 2+ = n x 1000 / 25 = 0.000897 M

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