The front 1.20 m of a 1,450-kg car is designed as a \"crumple zone\" that collap

Question

The front 1.20 m of a 1,450-kg car is designed as a "crumple zone" that collapses to absorb the shock of a collision.

The front 1.20 m of a 1,450-kg car is designed as a "crumple zone" that collapses to absorb the shock of a collision. If a car traveling 22.0 m/s stops uniformly in 1.20 m, how long does the collision last? What is the magnitude of the average force on the car? What is the magnitude of the acceleration of the car? Express the acceleration as a multiple of the acceleration of gravity.

Explanation / Answer

a. 1.2m = 21m/s * t So t=1.2/21=.06secs
b. F=ma where a=21m/s to 0m/s in .06sec
So F=1450*21/[1.2/21]=532,875N
c. a=21/.06 = 367.5 m/s^2 =37.5g

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