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A car traveled 240 km west, then 185 km south, then 160 km east, then 125 km nor

ID: 2143842 • Letter: A

Question

A car traveled 240 km west, then 185 km south, then 160 km east, then 125 km north. What is the total displacement of the car?

Explanation / Answer

Set up a x-y axis system. Start at origin. 185km south => y = -185 35km NE using pythagorean theorem: c^2 = a^2 + b^2 35^2 = 1225, 1225 / 2 = 612.5, square root (612.5) = 24.75 That is 24.75km east => x = 24.75 That is 24.75km north => y = 24.75 Add that to -185km you have -35.25km. New coordinate is 24.75 (east) and -35.25 (south). Then go 240km west => x = -240 Add that to 24.75 you have -25.25km. New coordinate is -125km (west) and -35.25 (south). Find displacement from origin (0,0). c^2 = a^2 + b^2 displacement^2 = (125.)^2 + (35.25)^2

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