In the form of radioactive decay known as alpha decay, an unstable nucleus emits

Question

In the form of radioactive decay known as alpha decay, an unstable nucleus emits a helium-atom nucleus, which is called an alpha particle. An alpha particle contains two protons and two neutrons, thus having mass m=4u and charge q=2e. Suppose a uranium nucleus with 92 protons decays into thorium, with 90 protons, and an alpha particle. The alpha particle is initially at rest at the surface of the thorium nucleus, which is 15fm in diameter.

What is the speed of the alpha particle when it is detected in the laboratory? Assume the thorium nucleus remains at rest.

Explanation / Answer

I cant explain it but i know the anwser is 4.1x10^7.

I think you have to find the accerelation by finding the amount of force the thorium nucleus exterts on the alpha particle then dividing it by the mass then plug it in to the Vf^2=Vi^2+2ad kinematic equation.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.