The drawing shows a large cube (mass = 20.9 kg) being accelerated across a horiz

Question

The drawing shows a large cube (mass = 20.9 kg) being accelerated across a horizontal frictionless surface by a horizontal force P. A small cube (mass = 4.9 kg) is in contact with the front surface of the large cube and will slide downward unless P is sufficiently large. The coefficient of static friction between the cubes is 0.71. What is the smallest magnitude that P can have in order to keep the small cube from sliding downward?

Number ? Units ?

Explanation / Answer

Frictional force = mg (for small block) = 0.71*Normal Force = 4.9g =>normal force should be = 67.63 N normal force = pseudo force = 67.63 = 4.9a acceleration = 13.8/s^2 P = a(M+m) = 356.11N

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