Water is moving with a speed of 8.0 m/s through a pipe with a cross-sectional ar

Question

Water is moving with a speed of 8.0 m/s through a pipe with a cross-sectional area of 3.5 cm2. The water gradually descends 20.0 m as the pipe's cross section increases by a factor of two. What is the speed of flow at the lower level? How much higher is the pressure at the lower level compared to the upper level?

Explanation / Answer

Water flux: v1*S1 = v2*S2 -> v2 = 8*3.5/7 = 4 m/s for pressure calculation Bernoulli: P1 + d*g*h1 + (1/2)d*v1^2 = P2 * d*g*h2 + (1/2)d*v2^2 -> P2 - P1 = d*g*H + (1/2)*d(v1^2-v2^2) -> P2 - P1= 10^3*9.8*20 + 0.5*10^3*(8^2-4^2)= 2.2*10^5 Pa

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