A crate with a mass of 169.5 kg is suspended from the end of a uniform boom with

Question

A crate with a mass of 169.5 kg is suspended from the end of a uniform boom with a mass of 78.3 kg. The upper end of the boom is supported by a cable attached to the wall and the lower end by a pivot (marked X) on the same wall. Calculate the tension in the cable.

A crate with a mass of 169.5 kg is suspended from the end of a uniform boom with a mass of 78.3 kg. The upper end of the boom is supported by a cable attached to the wall and the lower end by a pivot (marked X) on the same wall. Calculate the tension in the cable.

Explanation / Answer

torque: 8.5 T = 14 m g + 7.5 m' g T = (14*169.5*9.8+7*78.3*9.8)/8.5 >> T = 3368 N

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