A crate with a mass of 167.5 kg is suspended from the end of a uniform boom with

Question

A crate with a mass of 167.5 kg is suspended from the end of a uniform boom with a mass of 74.9 kg. The upper end of the boom is supported by a cable attached to the wall and the lower end by a pivot (marked X) on the same wall. Calculate the tension in the cable.

A crate with a mass of 167.5 kg is suspended from the end of a uniform boom with a mass of 74.9 kg. The upper end of the boom is supported by a cable attached to the wall and the lower end by a pivot (marked X) on the same wall. Calculate the tension in the cable.

Explanation / Answer

mass of the boom m = 167.5kg, tension T =734.02 N
angle of the cable with horizontal = ? = tan-1(3/11) = 15.255o
find mass of the crate M
net torque about X = mg*5.5 + Mg*11 - Tcos?*4 - Tsin?*11 = 0
M =

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