A 2.0-{\ m mol} sample of ideal gas with molar specific heat C_V = {\\textstyle{
ID: 2209045 • Letter: A
Question
A 2.0-{ m mol} sample of ideal gas with molar specific heat C_V = { extstyle{5 over 2}},R is initially at 320 K and 100 { m kPa} pressure.Part A
Determine the final temperature when 1.7 { m kJ} of heat are added to the gas isothermally.
Express your answer using two significant figures.
ANSWER:
T_f =
{ m K}
Part B
Determine the work done by the gas when 1.7 { m kJ} of heat are added to the gas isothermally.
Express your answer using two significant figures.
ANSWER:
W =
{ m kJ}
Part C
Determine the final temperature when 1.7 { m kJ} of heat are added to the gas at constant volume.
Express your answer using two significant figures.
ANSWER:
T_f =
{ m K}
Part D
Determine the work done by the gas when 1.7 { m kJ} of heat are added to the gas at constant volume.
Express your answer using two significant figures.
ANSWER:
W =
{ m J}
Part E
Determine the final temperature when 1.7 { m kJ} of heat are added to the gas isobarically.
Express your answer using two significant figures.
ANSWER:
T_f =
{ m K}
Part F
Determine the work done by the gas when 1.7 { m kJ} of heat are added to the gas isobarically.
Express your answer using two significant figures.
ANSWER:
W =
{ m J}
Explanation / Answer
part A
as the gas underwent isothermal there is no difference in temperature
final temperature=320K
part B
given T=0,
H=U+W,U=0 since isothermal process
W=H
=1.7 KJ
PART c
V=0,HENCE W=0
nCvdT=1.7
===>dT=1.7/5
=0.34 KJ
PART D
FOR constant volume process
work done is zero
part F
For isobaric process w=H-nCvdT
===>W=1.7-5*dT
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