A 2.10 kg hoop 2.10 m in diameter is rolling to the right without slipping on a

Question

A 2.10 kg hoop 2.10 m in diameter is rolling to the right without slipping on a horizontal floor at a steady 2.80 rad/s . PARTA: How fast is its center moving? (in m/s) PARTB: What is the total kinetic energy of the hoop? (in J) PARTC: Find the magnitude of the velocity vector of each of the following points, as viewed by a person at rest on the ground: (i) the highest point on the hoop; (ii) the lowest point on the hoop, (iii) a point on the right side of the hoop, midway between the top and the bottom. [separate the answers with commas] PARTE: Find the magnitude of the velocity vector for each of the points in part (C), except as viewed by someone moving along with same velocity as the hoop. [separate the answers with commas]

Explanation / Answer

KE = (0.5) * (2.80 kg) * (3.3 m/s)2 = 15.246 Kinetic energy is the energy of motion. An object that has motion - whether it is vertical or horizontal motion - has kinetic energy. There are many forms of kinetic energy - vibrational (the energy due to vibrational motion), rotational (the energy due to rotational motion), and translational (the energy due to motion from one location to another). To keep matters simple, we will focus upon translational kinetic energy. The amount of translational kinetic energy (from here on, the phrase kinetic energy will refer to translational kinetic energy) that an object has depends upon two variables: the mass (m) of the object and the speed (v) of the object

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