you have two identical pure silver ingots. You place one of them in a glass of w

Question

you have two identical pure silver ingots. You place one of them in a glass of water and observe it to sink to the bottom. You place the other in a container full of mercury and observe that it floats. Comparing the buoyant forces in the two cases you conclude that a.) the buoyant force in water is smaller than in mercury b.) the buoyant force in the water is larger than that in mercury c.) the buoyant force in the water is zero and that in mercury is non - zero d.) the buoyant force in the water is equal to that in mercury e.) no conclusion can be made about the respective values of the buoyant forces

Explanation / Answer

buoyancy force = VDg = volume X density X g density of mercury = 13.6 gm/cc density of water = 1gm /cc so, unless the volume is known, the buyoant force cant be figured out. e is the answer.

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.