A basketball of mass 0.638 kg is dropped from rest from a height of 1.44 m. It r

Question

A basketball of mass 0.638 kg is dropped from rest from a height of 1.44 m. It rebounds to a height of 0.691 m. (a) How much mechanical energy was lost during the collision with the floor? (b) A basketball player dribbles the ball from a height of 1.44 m by exerting a constant downward force on it for a distance of 0.106 m. In dribbling, the player compensates for the mechanical energy lost during each bounce. If the ball now returns to a height of 1.44 m, what is the magnitude of the force?

Explanation / Answer

a) mechanical energy lost = mg(h1-h2) = 0.638*9.8*(1.44-0.691) = 4.683 J b) so this lost energy is compensated by the dribbler; 4.683 =F*0.106 F = 44.179 N ----------->answer

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