A landscape architect is planning an artificial waterfall in a city park. Water

Question

A landscape architect is planning an artificial waterfall in a city park. Water flowing at 1.190 m/s will leave the end of a horizontal channel at the top of a vertical wall h = 2.50 m high and falls into a pool (see figure).(a) How far from the wall will the water land?_______m Will the space behind the waterfall be wide enough for a pedestrian walkway? (Assume the water must land 2 m from the wall to provide adequate space for a person to walk beneath the waterfall.) Yes No (b) To sell her plan to the city council, the architect wants to build a model to standard scale, one-thirteenth actual size. How fast should the water flow in the channel in the model?__________m/s I WOULD LIKE TO KNOW SPECIFICALLY WHICH EQUATIONS TO USE SO I CAN DO THIS ON MY OWN. PLEASE GIVE ME A DETAILS AS TO HOW YOU FIND THE ANSWERS SO I CAN DO THIS ON MY OWN! Thank youu

Explanation / Answer

in order to find how far the water will land, you need to multiply its horizontal velocity with the time it takes to fall to the ground.

ok. time taken for any body to fall to the ground from a height h = (2h/g)

so you can get the distance now = v*(2h/g)

ok. the scale is one thirteenth the actual size.

so both the gap and height would be drawn 1/13th their original value.

so u need such a v which satisfies these requirement

let the required speed be k times the original v. so,

kv*(2*(h/13)/g) = (distance found above)/13

from this, you can easily get k.

so the speed that must be shown in the p[lan = k*v

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