(a)Calculate the speed of a proton after it accelerates from rest through a pote

Question

(a)Calculate the speed of a proton after it accelerates from rest through a potential difference of 260 V. m/s (b) Calculate the speed of an electron after it accelerates from rest through a potential difference of 260 V. for (a) I got 5.70 e18 for (b) i got 9458454.715 I think (b) is wrong...Help pls. Work for (a) v=sqrt 2qV/m so is sqrt 8.32e-17C/1.6*10^-27 work for (b) is v=sqrt 2qV/m which is sqrt 2*(1.68*10^-19C)(260V)/(9.31*10^-31)

Explanation / Answer

(a) 0.5 m v^2 = q V ===> v = (2*qV/m)^0.5 = (2*1.6e-19*260/1.673e-27)^0.5 = 2.23E5 m/s

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