A diverging lens of focal length -11.2 cm is placed 40.0 cm from a converging le

Question

A diverging lens of focal length -11.2 cm is placed 40.0 cm from a converging lens of unknown focal length. A 15.2 cm tall erect object is placed 20.3 cm in front of the diverging lens which is to produce an image on a screen that is twice the size of the original object but inverted. 1.Where should the screen be located to produce a clear image? Give the distance from the converging lens to the screen in cm. 2.What is the focal length of the converging lens? 3.What is the height of the intermediate image formed by the diverging lens? 4.If the screen is removed and the image is viewed using your eyes instead, what angular magnification would result from placing your eyes 40 cm from the final image?

Explanation / Answer

55 cm. The rays emerging to the right of the diverging lens diverge from the virtual image located 15 cm to the left of the diverging lens or 55 cm to the left of the converging lens. Since the rays emerge from the converging lens parallel, the focal length of the converging lens is 55 cm. See the refs.

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