The figure below shows a bar of mass m = 0.300 kg that can slide without frictio

Question

The figure below shows a bar of mass m = 0.300 kg that can slide without friction on a pair of rails separated by a distance scripted l = 1.20 m and located on an inclined plane that makes an angle ? = 30.0 degree with respect to the ground. The resistance of the resistor is R = 1.80 ? and a uniform magnetic field of magnitude B = 0.500 T is directed downward, perpendicular to the ground, over the entire region through which the bar moves. With what constant speed v does the bar slide along the rails?

Explanation / Answer

F=mgsin(x) =0.3*9.8*sin30

F=1.47 N

and

F=BILcos(x)

1.47 =0.5*i*1.2*cos30

I =2.83 A

E=IR =2.83*1.8 =5.092 V

E=BLVcos(x)

5.092 =0.5*1.2*V*cos30

V =9.8 m/s

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