A light spring of constant k = 170 N/m rests vertically on the bottom of a large

Question

A light spring of constant k = 170 N/m rests vertically on the bottom of a large beaker of water (as seen in the picture below).

An m = 5.78 kg block of wood (density = 637 kg/m3) is connected to the spring and the mass-spring system is allowed to come to static equilibrium (b). What is the elongation, DeltaL,  of the spring?

A light spring of constant k = 170 N/m rests vertically on the bottom of a large beaker of water (as seen in the picture below). An m = 5.78 kg block of wood (density = 637 kg/m3) is connected to the spring and the mass-spring system is allowed to come to static equilibrium (b). What is the elongation, DeltaL, of the spring?

Explanation / Answer

Bouyancy force is
mg*(1-pH2O/pwood)
5.5*9.81*(1-1000/632)=-31.4

kx=F

x=31.4/166=.19m

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