The question is: The valence band in Si has width of 12 eV. In a cube of Si that
ID: 2241509 • Letter: T
Question
The question is:
The valence band in Si has width of 12 eV. In a cube of Si that measures 1.0 mm on each side, calculate (a) the total number of states in the valence band, and (b) the average spacing between the states. The density of sodium is 2.33 g/(cm^3).
Not really sure how to go about solving this. I know that the conduction bands electrons will equal to the empty states in the valence band, but I'm not given any noticeable structure on how to find that value. Please help! Not really sure how to go about solving this. I know that the conduction bands electrons will equal to the empty states in the valence band, but I'm not given any noticeable structure on how to find that value. Please help!Explanation / Answer
total number of states in sodium n = (2/3)*gamma* E^(3/2)
where gamma is a constant who's value is 6.82*10^(27)
putting the value in the equation we get (2/3)* (6.82*10^(27)*12^(3/2)
so the number of state =188.97*10^27
the energy level of nth state can be calculated by the formula {n(x)^(2)*h^(2)}/{8m*L^(2)}
where h is plank constant, m is mass of electron and L is the dimension of the cubeic crystal.
putting n = 1,2,3 we can calculate the energy of the electron state and the average value of state energy spacing comes out to be 2.4*10^(-34) joules
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