Question Part Points Submissions Used 1. Two long parallel wires, each carrying

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Question Part Points Submissions Used 1. Two long parallel wires, each carrying a current of 11 A, lie a distance of 10 cm from each other. What is the magnetic force per unit length exerted by one wire on the other?
N/m

If the distance between the two wires is tripled, what is the new force per unit length?
N/m
2. A particle with a charge of 0.8 C is moving at right angles to a uniform magnetic field with a strength of 0.6 T. The velocity of the charge is 620 m/s. What is the magnitude of the magnetic force exerted on the particle? N

Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used 1. Two long parallel wires, each carrying a current of 11 A, lie a distance of 10 cm from each other. What is the magnetic force per unit length exerted by one wire on the other?
N/m

If the distance between the two wires is tripled, what is the new force per unit length?
N/m
2. A particle with a charge of 0.8 C is moving at right angles to a uniform magnetic field with a strength of 0.6 T. The velocity of the charge is 620 m/s. What is the magnitude of the magnetic force exerted on the particle? N 1. Two long parallel wires, each carrying a current of 11 A, lie a distance of 10 cm from each other. What is the magnetic force per unit length exerted by one wire on the other?
N/m

If the distance between the two wires is tripled, what is the new force per unit length?
N/m
2. A particle with a charge of 0.8 C is moving at right angles to a uniform magnetic field with a strength of 0.6 T. The velocity of the charge is 620 m/s. What is the magnitude of the magnetic force exerted on the particle?
Question Part Points Submissions Used

Explanation / Answer

magnetic force between parallel wires is given by F = uoi1i2l/2pir

F/l = 4pi*10^-7 * 11*11/(2pi*0.1)

F/l = 2.42*10^-4 N/m

b. if distance is tripled,

F/l = 4pi*10^-7 * 11*11/(2pi*3*0.1)

F/l = 0.8066 *10^-4 N/m

2. magnetic force F = qvB

F = 0.8* 620 * 0.6

F = 297.6 N

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