A 0.250kg block of ice is placed against a horizontal, compressed spring mounted

Question

A 0.250kg block of ice is placed against a horizontal, compressed spring mounted on a horizontal tabletop that is 2.04m above the floor. The spring is initially compressed 6.10cm. The mass of the spring is negligible. The spring is released, and teh block slides along the table, goes off the edge, and travels to the floor. If there is negligible friction between the block of ice and the table top, and the ice reaches the floor with a speed of 7.18m/s, what is the spring constant?

The answer is k=777n/m

Please work the problem

Explanation / Answer

energy conservation

0.5 k x^2 = 0.5 mv^2 + mg delta h

v = 7.18

x =0.0610 m

delta h = 2.04

m = 0.250 kg

on substituting this we get

k = 78.44 N/m

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