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A block of mass m = 2.00 kg is attached to a spring of force constant k = 600 N/

ID: 2257872 • Letter: A

Question

A block of mass m = 2.00 kg is attached to a spring of force constant k = 600 N/m as shown in the figure below. The block is pulled to a position xi = 4.55 cm to the right of equilibrium and released from rest.

A block of mass m = 2.00 kg is attached to a spring of force constant k = 600 N/m as shown in the figure below. The block is pulled to a position xi = 4.55 cm to the right of equilibrium and released from rest. Find the speed the block has as it passes through equilibrium if the horizontal surface is frictionless. m/s Find the speed the block has as it passes through equilibrium (for the first time) if the coefficient of friction between block and surface is ?k = 0.350. m/s

Explanation / Answer

a) W = 1/2*k*x^2 and so W = 0.5 * 600[N/m] * (.0445m)^2 = 0.5940 J

b) KE = [delta]W = 0.5940
KE = 1/2 * m * v^2
rearrange so that v = sqrt(2*KE/m) = = sqrt(0.5940[m^2/s^2]) = 0.7707 m/s

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