An air puck of mass m 1 = 0.15 kg is tied to a string and allowed to revolve in

Question

An air puck of mass m1 = 0.15 kg is tied to a string and allowed to revolve in a circle of radius R = 0.9 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of m2 = 1.2 kg is tied to it (see the figure below). The suspended mass remains in equilibrium while the puck on the tabletop revolves.

An air puck of mass m1 = 0.15 kg is tied to a string and allowed to revolve in a circle of radius R = 0.9 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of m2 = 1.2 kg is tied to it (see the figure below). The suspended mass remains in equilibrium while the puck on the tabletop revolves. What is the tension in the string? N What is the horizontal force acting on the puck? N What is the speed of the puck? m/s

Explanation / Answer

a) T =m2g = 1.2 x 9.8 =11.76 N

b) F = T =11.76 N

c) F = mv^2 /r

11.76 = 0.15v^2 / 0.9

v = 8.4 m/s

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