A block of mass 43 kg is sliding along on a frictionless table with a velocity o

Question

A block of mass 43 kg is sliding along on a frictionless table with a velocity of magnitude 4 m/s. (Call this the +x direction.) It splits into three pieces after an internal explosion- one with mass 14 kg goes off in the +x direction with velocity of magnitude 5 m/s. A second piece, mass 14 kg, goes off perpendicular to the original direction, but still in the plane of the table, with velocity 5 m/s. (Call this the +y direction.) Find the x component of the velocity of the third piece

The answer is 6.8, but not sure how to get there. Please help!

Explanation / Answer

applying conservation of momentum in x direction we have

43*4=14*5+15*vx

vx=6.8 m/s

for x component you have to consider only conservation of momentum along x direction Do not take the Y component of velocity Thanks

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