A 148 gram baseball is hit toward the left by a bat. The magnitude of the force
ID: 2263598 • Letter: A
Question
A 148 gram baseball is hit toward the left by a bat. The magnitude of the force the bat exerts on the ball as a function of time is shown in the figure below (Figure 1) . A 148 gram baseball is hit toward the left by a bat. The magnitude of the force the bat exerts on the ball as a function of time is shown in the figure below (Figure 1) . A 148 gram baseball is hit toward the left by a bat. The magnitude of the force the bat exerts on the ball as a function of time is shown in the figure below (Figure 1) . A 148 gram baseball is hit toward the left by a bat. The magnitude of the force the bat exerts on the ball as a function of time is shown in the figure below (Figure 1) . Part A Find the magnitude of the impulse that the bat imparts to the ball. p = kg?m/s Part B Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially at rest. v = m/s Part C Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . v = m/s Part F Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5 . to the left to the right Provide FeedbackContinue Part A Find the magnitude of the impulse that the bat imparts to the ball. p = kg?m/s Part B Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially at rest. v = m/s Part C Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . v = m/s Part F Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5 . to the left to the right Part A Find the magnitude of the impulse that the bat imparts to the ball. p = kg?m/s Part B Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially at rest. v = m/s Part C Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . v = m/s Part F Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5 . to the left to the right Part A Find the magnitude of the impulse that the bat imparts to the ball. p = kg?m/s Part B Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially at rest. v = m/s Part C Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . v = m/s Part F Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5 . to the left to the right Part A Find the magnitude of the impulse that the bat imparts to the ball. p = kg?m/s Part A Find the magnitude of the impulse that the bat imparts to the ball. p = kg?m/s p = kg?m/s p = kg?m/s Part B Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially at rest. v = m/s Part B Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially at rest. v = m/s v = m/s v = m/s Part C Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . v = m/s Part C Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . v = m/s v = m/s v = m/s Part F Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5 . to the left to the right Part F Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5 . to the left to the right Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5 . to the left to the right Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5 . to the left to the right Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5 . to the left to the right Provide FeedbackContinue Figure 1 of 1 p = kg?m/s A 148 gram baseball is hit toward the left by a bat. The magnitude of the force the bat exerts on the ball as a function of time is shown in the figure below (Figure 1) . Find the magnitude of the impulse that the bat imparts to the ball. Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially at rest. Find the magnitude of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/s . Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5m/ Find the direction of the ball's velocity just after it is hit by the bat if the ball is initially moving to the right at 29.5 .Explanation / Answer
A) I = area under F-t graph = 0.003 x 4000 = 12 kg m/s
direction of Impulse = direction of average force = to the left (its provided in the qn)
B) Using momentum-impulse theorem,
delta p = I
mv_f - 0 = I
v_f = I/m = 12/0.148 = 81.08 m/s
C Using the momentum-impulse theorem
delta p = I
mv_f - mv_i = I
v_f = (I + mv_i)/m = -51.58 m/s --> the magnitude is 51.58 m/s
F) Since the qn stated 29.5 m/s as the positive value of the velocity of the ball when it was moving to the right, the negative value of our answer in part C means that the ball is moving to the left.
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