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You are assigned the design of a cylindrical, pressurized water tank for a futur

ID: 2263690 • Letter: Y

Question

You are assigned the design of a cylindrical, pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 meters per second per second. The pressure at the surface of the water will be 115kPa , and the depth of the water will be 13.9m . The pressure of the air in the building outside the tank will be 85.0kPa .


Find the net downward force on the tank's flat bottom, of area 2.50m2 , exerted by the water and air inside the tank and the air outside the tank


Express your answer numerically in Newtons, to three significant figures.

Explanation / Answer

(i) Pressure due to air outside, p1 = 85.0 kPa (ii) Pressure due to the water of height 13.9 m is, p2 = hdg = 13.9x1000x3.71= 51.569 kPa (iii) Pressure due to air inside thank, above the water, p3 = 115 kPa Total pressure on the florr under the tank, p = 85.0 + 51.57 + 115 = 251.57 Total force exeted on the floor, F = p.A = 251.57x103 x2.50 = 6.29x105 N
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