You are assigned the design of a cylindrical, pressurized water tank for a futur

Question

You are assigned the design of a cylindrical, pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 meters per second per second. The pressure at the surface of the water will be 140kPa , and the depth of the water will be 13.8m . The pressure of the air in the building outside the tank will be 86.0kPa .

Find the net downward force on the tank's flat bottom, of area 1.95m2 , exerted by the water and air inside the tank and the air outside the tank.

Express your answer numerically in Newtons, to three significant figures.

Explanation / Answer

There are three presurre acting which when combined will lead us to our answer....

1) Pressure due to Atmsphere....

2)Pressure due to weight of pressurised tank....

3)Pressure due to Height of water in the tank...

Atmospheric pressure = 86 KPa

Pressure at the surface of the water = 140KPa

)Pressure due to Height of water in the tank = density of water * Accelaratioon due to gravity* Height = 1000 * 3.71* 13.8 = 51.198KPa

Total pressure = 86 + 140 + 51.198=51.424 KPa

Total Force at bottom = P*A = 100.276N

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