A certain object weighs 22.2 N on the surface of Earth. If the radius of the moo

Question

A certain object weighs 22.2 N on the surface of Earth. If the radius of the moon is 0.276 times the radius of Earth and the mass of the moon is 0.0123 times the mass of Earth, the object's weight on the surface of the moon is approximately

I need to know how to do it, not just the answer thank you

A certain object weighs 22.2 N on the surface of Earth. If the radius of the moon is 0.276 times the radius of Earth and the mass of the moon is 0.0123 times the mass of Earth, the object's weight on the surface of the moon is approximately

Explanation / Answer

radius of the moon is 0.276 times the radius of earth and the mass is 0.0123 times the mass of the earth, the force will be:
W(moon) = G*(0.0123M)*m/(0.276r)^2 = (0.1615)*(G*M*m/r^2) = (0.1615)*(W(earth))

Since the object weighs 22.2 N on earth, its weight on the moon is:
W(moon) = 0.1615*W(earth) = (0.1615)*(22.2 N) = 3.58 N

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