An electron has an initial velocity of 8.00 ? 10 6 m/s in a uniform 9.00 ? 10 5

Question

An electron has an initial velocity of 8.00 ? 106 m/s in a uniform 9.00 ? 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity.

(a) What is the direction of the electric field?
1---Select---same direction as the electron's initial velocityopposite direction to the electron's initial velocitynot enough information to decide
(b) How far does the electron travel before coming to rest?
2 m
(c) How long does it take the electron to come to rest?
3 s
(d) What is the electron's speed when it returns to its starting point?
4 m/s

Explanation / Answer

a) opposite to the direction of electric field

b) v^2 =u^2-2as

v=0

s=0.0202 mm

c)v=u-at

t=5.055*10^-11 sec

d) same as initial speed u= 8*10^6 m/s

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