Find the equivalent capacitance of the circuit and the total charge absorbed by

Question

Find the equivalent capacitance of the circuit and the total charge absorbed by the circuit.

Capacitors C1 = 848 mu F, C2 = 648 mu F and C3 = 161 mu F, are placed in series with a 4.28 V battery. Find: - the equivalent capacitance of the circuit: CTOT = mu F - the total charge absorbed by the circuit: qTOT = mu C Capacitors C1 = 301 mu F, C2 = 682 mu F and C3 = 972 mu F, are placed in parallel with a 5.49 V battery. Find: - the equivalent capacitance of the circuit: CTOT = mu F - the total charge absorbed by the circuit: qTOT = mu F

Explanation / Answer

2>

1/[1/c1+1/c2+1/c3]=4.23*10^-6 F=4.23uF

charge=c*v=18.1 uC

3>

c1+c2+c3=1955 uF

charge=1955*5.4910732.95 uC

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