A ball of mass 2.30kg and radius 0.127m is released from rest on a plane incline

Question

A ball of mass 2.30kg and radius 0.127m is released from rest on a plane inclined at an angle theta=40.0 degrees with respect to the horizontal. How fast is the ball moving (in m/s) after it has rolled a distance d=1.40m? Assume that the ball rolls without slipping, and that its moment of inertia about its center of mass is 1.50 A ball of mass 2.30kg and radius 0.127m is released from rest on a plane inclined at an angle theta=40.0 degrees with respect to the horizontal. How fast is the ball moving (in m/s) after it has rolled a distance d=1.40m? Assume that the ball rolls without slipping, and that its moment of inertia about its center of mass is 1.50

Explanation / Answer

let the speed of the ball is v.

then initial potential energy=final potential energy+final rotational kinetic energy+final kinetic energy

change in potential energy=final kinetic energy+final rotational kinetic energy

2.3*9.8*1.4*sin(40)=0.5*2.3*v^2+0.5*1.5*10^(-2)*(v/0.127)^2

v=3.54 m/s

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