A capacitor with circular plates (of radius R) is discharged at time t=0, when a

Question

A capacitor with circular plates (of radius R) is discharged at time t=0, when a switch is closed and a constant flow of charge, I, is then allowed to flow onto its plates. Knowing that, from Gauss' Law, the electric field between the plates is constant and proportional to the charge density... C = E0A/d E = sigma/E0 I walk a semicircular path around the edge of the capacitor and then cut straight through the center, enclosing half of the plates' cross-sectional area. Evaluate the integral B.dl for this closed path. Note: This should be a one-time answer! What is the magnetic field strength as a function

Explanation / Answer

a.) I/2 as only half of the area is covered

b.) meu(naught)*I/(2*pie*R) by Ampere's Circuital Law

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